March 5th, 2008 . by Vanaja
The two cylindrical pans are similar. The diameter of the smaller pan is equal to the radius of the larger pan. How many of these smaller cans could fill the larger can?
Hint: Since the two cylinders are similar, their dimensions are in the same ratio. It is given that the diameter of the smaller pan is same as the radius of the larger pan. That is the radius of the two pans are in the ratio 2:1. In other words we can say if the radius of the larger pan is ‘r’ the radius of the smaller pan is r/2 and since they are similar their heights are also in the same ratio 2:1. So, if h is the height of the larger triangle, h/2 is the height of the smaller triangle.
Now,
Volume of the larger cylinder V_{l}= pi r^{2}h
Volume of the smaller cylinder V_{s}=pi(r/2)^{2}(h/2) =(pir^{2}h )/8 = V_{l}/8
i.e V_{s} =V_{l }/8
Therefore 8 smaller pans can fill one larger pan.
Posted in Algebra, Geometry, Problems and Solutions 
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February 27th, 2008 . by Vanaja
The following figures represent a relationship between two variables.
Which rule relates x the number of dark squares to y, the number of white squares?
Ans:
y=2x+3
Posted in Algebra, Problems and Solutions 
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February 17th, 2008 . by Vanaja
Sarah went to a grocery shop. There was a sales chart.
Items 
Price 
Cabbage 
$1.8 for 2

Carrot 
$0.6 for 1.k.g 
Onion 
$1.75 for 1 carton

Potato 
$2.05 for 1 carton

Tomato 
$1 for 1 k. 
Sarah bought 4 carton potatoes and 1 cabbage. If she gave $10, how much money she got back?
Hint: 10{(4×2.05)+.9}
Posted in Algebra, Arithmetic, Problems and Solutions 
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September 9th, 2007 . by Vanaja
A group consists of 50 students. Out of these 20 are girls .There are 10 Australian students. Out of 50 students, 25 students like cricket.
What is the probability of selecting an Australian girl who likes cricket?
Hint:
Probability of selecting a girl= 20/50
Probability of selecting an Australian student = 10/50
Probability of a student like cricket=25/50
Therefore the the probability of selecting an Australian girl who likes cricket= (20/50 )(10/50)(25/50) = 1/25 =0.25
Posted in Problems and Solutions, Statistics 
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August 29th, 2007 . by Vanaja
The following is the net representation of a cube.
How will you place the letters L, A, F on the figure so that it should spell LEAF around the sides of the cube?
Posted in Geometry, Problems and Solutions, Puzzles 
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August 21st, 2007 . by Vanaja
At a football championship 600 tickets were sold .
Child ticket cost $2 each and adult ticket cost $5 each. The total money collected for the game was $1650.
Find the number of tickets sold in each category.
Hint:
Let x be number of children and y be number of adults.
x+y = 600
2x+5y= 1650
==>x= 450, y=150
Posted in Algebra, Math Homework Help, Problems and Solutions 
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May 30th, 2007 . by Vanaja
Today we have a questions on percentage.
Ana is working in a restaurant as a bearer.
As a penalty Ana’s wages were decreased by 50%.
After one month the reduced wages were increased by 50%.
Find her loss.
Hint: The salary increased is the 50% of the decreased salary.
Answer:
New salary is 50+25=75
Therefore loss=25%
Posted in Arithmetic, Problems and Solutions 
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May 5th, 2007 . by Vanaja
Today we have a problem on triangle
Hint:
Since AB=BC, angle C= angle A (Angles opposite to equal sides are equal)
Also, Sum of the angles is 180 º
Answer
55 º
Posted in Geometry, Problems and Solutions, Triangles 
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April 18th, 2007 . by Vanaja
John has a rectangular lawn of dimensions 50 meter by 40 meter.
It has two roads each 2 meter wide running in the middle of it one parallel to the length and one parallel to the breadth. He wants to tar the road.
Find area of the roads to be tarred.
Hint:
We have two roads to be tarred. One is horizontal and the other is vertical.
So, area to be tarred is the area of the two roads which are rectangular in shape.
Area of a rectangle is length x breadth.
Area of the horizontal road = 2 x 50=100 sq.m
Area of the vertical road = 2 x 40=80 sq.m
So,the total are of the two roads=100+80=180 sq.m
But, the roads are crossing at the middle. It is a square portion of sides 2m by 2m in dimensions and we can see that two times we added that area. So, we should subtract that area from the total area of the two rectangular roads.
Area of the square portion is 2 x 2=4 sq.m
Therefore, the area to be tarred = Total area of the two rectangles  The common area
Ans: 176 sq.m
Posted in Area, Problems and Solutions 
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April 17th, 2007 . by Vanaja
The average temperature of for Monday, Tuesday and Wednesday was 30ºC.
The average temperature for Tuesday, Wednesday and Thursday was 29º C. The Temperature on Thursday was 32º C.
What was the temperature on Monday?
Hint:
Total temperature on Mon,Tue and Wed = 30ºC*3 = 90ºC
Total temperature on Tue,Wed and Thu = 29ºC*3 = 87ºC
Total temperature on Tue and Wed = Total temperature on Tue, Wed and Thu Temperature on Thu = 87ºC32ºC= 55ºC
Now, Temperature on Monday can be calculated as follows
Temperature on Monday = Total temperature on Mon,Tue and WedTotal temperature on Tue and Wed
Ans: 35ºC
Posted in Average, Problems and Solutions 
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